Question

121÷[16-{14-3(9-6)}]

Answer 1

hiii friend
here is your answer
$= \frac{121}{(16 -( 14 - 9(9 - 6)))} \\ = \frac{121}{(16 -(14 - 3(3))) } \\ = \frac{121}{16 - (14 - 9)} \\ = \frac{121}{16 - ( 5)} \\ = \frac{121}{16 -5} \\ = \frac{121}{11} \\ = 11$
glad to help you
hope it helps
thank you.

Answer 2

Answer:

121

121÷[16-{14-3(9-6)}]