Question

(121/21-8√
$(121/21-8 \sqrt{5} )-(88/4- \sqrt{5} )$
5)-(88/4-√5)​

Answer 1

Answer:

$\frac{161\sqrt{5} }{40} -\frac{6}{5}$

Step-by-step explanation:

Rationalizing the denominator-

$\frac{121}{8\sqrt{5} } \times\frac{8\sqrt{5} }{8\sqrt{5}} \\\\= >\frac{968\sqrt{5} }{320}$

$(\frac{968\sqrt{5} }{320}) -(\frac{88}{4}-\sqrt{5} )\\\\=>\frac{968\sqrt{5} }{320} -\frac{88}{4}+\sqrt{5} \\\\=>\frac{968\sqrt{5}-704+320\sqrt{5} }{320} \\\\=>\frac{1288\sqrt{5}-384 }{320} \\\\=>\frac{1288\sqrt{5} }{320}-\frac{384}{320}\\\\=>\frac{161\sqrt{5} }{40} -\frac{6}{5}$