Math, asked by angkitaborah128, 10 months ago

121 b square - 88 BC + 16 C square​

Answers

Answered by itzvishuhere
9

Heya mate!!

121 {b}^{2}  - 88bc + 16 {c }^{2}  \\  \sqrt{ {11b}^{2} }  - 2 \times 11 \times 4 \times bc +  \sqrt{ {4c}^{2} }  \\(  {11b - 4c})^2

Hope it helps you dear✌️✌️

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