Question

121) Prove that secA(I-sinA) (secA+tanA)=1​

Answer 1

Answer:

LHS=RHS

1=1

Step-by-step explanation:

The Steps are given above in the Attachmentbut these will help you understand the Concept and formulas used in that:-

• We first used the relations like quotient relations,square relations and the normal relations: like for 1-sin²A=cos²A and SecA=1/cosA and TanA=sinA/CosA
• And finally use those Relations to Prove the above Question I.E PROVE LHS=RHS.

hope You understand✓

Answer 2

Answer:

1

Step-by-step explanation:

L.H.s=(secA-secAsinA)(secA+tanA)

(secA-1/cosA ×sinA)(secA+tanA)

(secA-tanA)(secA+tanA)

sec^2A-tan^2A ((a-b)(a+b)=a^2-b^2)

1

R.H.S