Question

121. What least number must be added to 41116, so that
the sum is completely divisible by 8?​

Answer 1

Answer:

Step-by-step explanation:

Here The Intial Number is 41,116 and Let the least number added be X so it is completely divisible by 8

Since

41,116/8 =5,139.50 now rounded up value will be 5140

Now

5,140 multiply 8 gives you 41,120

So X = 41,120-41,116=4

Hence least number added to 41,116 is 4 which makes 41,120 and thus 41,120 is divisible by 8