Math, asked by StarTbia, 1 year ago

12167 - What will be the 'digit at unit place in the cube root of the given number.

Answers

Answered by HappiestWriter012
4
We know that,

A number multiplied by itself three times then it is called Perfect cube.

A number ending with 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 0 then it's cube ends with 1 , 8 , 7 , 4 , 5 , 6 , 3 , 2 , 0 respectively.

So, Here 12167 is the cube of some number.

12167 ended with 7 , so it's cube root should end with 3

Let's check it out,

Cube root of 12167

 \sqrt[3]{12167}

 \sqrt[3]{23 \times 23 \times 23 } \\ \\ = \sqrt[3]{ {23}^{3} } \\ \\ = 23

Therefore, Cube root of 12167 ends with 3 or

you can say that, Digit in the units place of cube root of 12167 is 3
Answered by mysticd
3
From the table attached above ,

we can see that If a number has 7 in

the unit place , then it's cube root

ends with 3 .

Here ,

Given number 12167 has 7 in the unit

place , then it's cube root ends with 3.

Or

12167 = ( 23 )³

Cube root of ( 12167 ) = 23( unit digit 3 )

I hope this helps you.

: )

Attachments:
Similar questions