Question

121a^2+198ab+81 simplify using identities
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Answer 1

Step-by-step explanation:

Step by Step Solution:

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STEP

1

:

Equation at the end of step 1

((121 • (a2)) + 198ab) + 34b2

STEP

2

:

Equation at the end of step

2

:

(112a2 + 198ab) + 34b2

STEP

3

:

Trying to factor a multi variable polynomial

3.1 Factoring 121a2 + 198ab + 81b2

Try to factor this multi-variable trinomial using trial and error

Found a factorization : (11a + 9b)•(11a + 9b)

Detecting a perfect square :

3.2 121a2 +198ab +81b2 is a perfect square

It factors into (11a+9b)•(11a+9b)

which is another way of writing (11a+9b)2

How to recognize a perfect square trinomial:

• It has three terms

• Two of its terms are perfect squares themselves

• The remaining term is twice the product of the square roots of the other two terms

Final result :

(11a + 9b)2

Answer 2

$121a^{2} +198ab+81b^{2} \\= (11a)^{2} +2.11a.9b+(9b)^{2} \\= (11a+9b)^{2} Ans.$

I hope it help you.