Question

121b^2 - 88bc + 16c^2​

Answer 1

Step-by-step explanation:

$121 {b}^{2} - 88bc + 16 {c}^{2}$

Formula to be used:

$(a - b)^{2} = a^{2} - 2ab + b^{2}$

Solving:

$121 {b}^{2} - 88bc + 16 {c}^{2} = (11b)^{2} - 2 \times 11b \times 4c + (4c) ^{2}$

$= (11b - 4c)^{2}$

HOPE IT HELPS :)