Math, asked by nensi1230, 4 months ago

121b^2-88bc+16c^2 Use factorization method

Answers

Answered by swarnalatasamal

0

Answer:

121b^2-88bc+16c^2=0

=(11b) ^2-2×11b×4c+(4c) ^2=0

=(11b-4c) ^2=0

=b=4c/11

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