French, asked by Shinyy, 11 months ago

121b²+22b+1 ? factorisation

Answers

Answered by Trisha3010

4

Answer:

$121{b}^{2} + 22b + 1 \\ 121 { b}^{2} + 11b + 11b + 1 \\ 11b(11b + 1) + 1(11b + 1) \\( 11b + 1)(11b + 1) \\ (11b + 1) ^{2}$

hope this will help u....

Answered by mohanakrishnasaiv

0

Answer:

(11b+1)(11b+1)

Explanation:

121b^2+ 22b+1

=121b^2+11b+11b+1

=11b^2(11b^2+1)+1(11b62+1)

=(11b+1)(11b+1)

=(11b+1)^2

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