Question

121x^2/289-y^2
ans plz​

Answer 1

Answer:

$\frac{121 {x}^{2} }{289} - {y}^{2} \\ = {( \frac{11x}{17}) }^{2} - {y}^{2} \\ = ( \frac{11x}{17} - y)( \frac{11x}{17} + y)$

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