Question

121x^4-81x^2 factorize​

Answer 1

Answer:

kuch bhi

Step-by-step explanation:

Answer 2

Given expression:

$121x^{4} -81x^{2}$.

Here, numbers $121$ and $81$ are perfect squares.

$121$ and $81$ are square values of $11$ and $9$ respectively.

So, given expression can be written as:

$(11x^{2} )^{2} -(9x)^{2}$

Above expression is in the form of $a^{2} -b^{2}$.

By using the identity: $[a^{2} -b^{2} =(a+b) (a-b)]$.

Here, $a=11x^{2}$ and $b=9x$.

$\implies(11x^{2} )^{2} -(9x)^{2}=(11x^{2} +9x)(11x^{2} -9x)$.

Hence, $(11x^{2} +9x)(11x^{2} -9x)$ is the factorized form of $121x^{4} -81x^{2}$.