Math, asked by zahrafatma5froll48, 2 months ago

122.9°F answer waht is answer​

Answers

Answered by Anonymous
7

Correct Question :

Convert 122.9 °F to °C

Required Answer :

Kindly refer the attachment for your answer!

Conversion of Temperature :

• To convert Fahrenheit to Celsius we use the formula F = C × \sf\dfrac{9}{5} + 32

• To convert Celsius to Fahrenheit we use the formula C = ( F - 32 ) × \sf\dfrac{5}{9} + 32

For example,

1. Convert 30 °C to °F

2. Convert 95 °F to °C

Note : Solutions are attached

Temperature :

• The temperature is the measure of how hot or cold an object is.

• The thermometer is the instrument used for measuring temperature

• Temperature is measured in degrees and the symbol of degree is °.

There are two types of temperature scales :

a) Celsius Scale ( Marked from 0° to 100° and is read as degree Celsius °C )

b) Fahrenheit Scale ( Marked from 0° to 220° and is read as degree Fahrenheit °F )

Remember :

\boxed{\begin{array}{c|c|c} \bf C^o & \bf F^o & \bf Description\\ \sf \dfrac{\qquad \qquad \qquad \qquad}{100} & \sf \dfrac{\qquad \qquad}{212} & \sf  \dfrac{\qquad \qquad \qquad \qquad}{Boiling\:point\:of\:water} \\ \sf \dfrac{\qquad \qquad \qquad \qquad}{40} & \sf \dfrac{\qquad \qquad}{104} & \sf  \dfrac{\qquad \qquad \qquad \qquad}{Hot\:Bath} \\ \sf \dfrac{\qquad \qquad \qquad \qquad}{37} & \sf \dfrac{\qquad \qquad}{98.6} & \sf  \dfrac{\qquad \qquad \qquad \qquad}{Normal\:body\:temperature} \\ \sf \dfrac{\qquad \qquad}{30} & \sf \dfrac{\qquad \qquad}{86} & \sf  \dfrac{\qquad \qquad \qquad \qquad}{Beach\:weather} \\ \sf \dfrac{\qquad \qquad}{0} & \sf \dfrac{\qquad \qquad}{32} & \sf  \dfrac{\qquad \qquad \qquad \qquad}{Freezing\:point\:of\:water}\end{array}}

\boxed{\begin{array}{c|c|c} \bf Water & \bf Celsius\:Scale & \bf Farenheit\:Scale\\ \sf \dfrac{\qquad \qquad \qquad \qquad}{Freezing\:Point} & \sf \dfrac{\qquad \qquad}{0\:C^o} & \sf  \dfrac{\qquad \qquad \qquad \qquad}{32\:F^o} \\ \sf \dfrac{\qquad \qquad \qquad \qquad}{Boiling\:Point} & \sf \dfrac{\qquad \qquad}{100\:C^o} & \sf  \dfrac{\qquad \qquad \qquad \qquad}{212\:F^o}\end{array}}

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