Question

122. It 2 cos2 0 + sin 0 - 2 = 0 and 0° < 0 < 90°;
find the value of 0.
​

Answer 1

Answer:

(3x−5)(3x−5)

= 9{x}^{2} - 15x - 15x - + 25=9x

2

−15x−15x−+25

= 9 {x }^{2} - 30x + 25=9x

2

−30x+25

$(3x−5)(3x−5) \\ = 9{x}^{2} - 15x - 15x + 25 </p><p> \\ = 9 {x }^{2} - 30x + 25</p><p></p><p>$