Physics, asked by parmarsneh, 1 year ago

123. The initial velocity of particle moving along a
straight line is 10 m/sec and its retardation is
2 m/sec2, the distance moved by the particle
in the fifth second of its motion is:
(a) 1 m
(b) 19 m
(c) 50 m
(d) 75 m​

Answers

Answered by anjali191103
1

Explanation:

s=a+u/2(2n+1)

=2+5(11)

2+55

57 metre

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