Question

123. The radius of the orbit of a geosynchronous satellite is 36000 km. Then the period of revolution of a satellite with its orbital radius 9000 km would be​

Answer 1

Answer:

Thus we can write: (TsTg)2=(RsRg)3⇒(Ts24)=(900036000)3/2⇒Ts=24×(14)3/2⇒Ts=24×(18)⇒Ts=3hrs. Thus the required time period of the satellite is 3 hours.

Explanation:

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