Question

1234⅖÷12315 ×1256 +5362
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Answer 1

Step-by-step explanation:

AnSweR:

Given,

→\;{\sf{\frac{x-5}{2}-\frac{x-3}{5} = \frac{1}{5}}}→2x−5−5x−3=51

The LCM of 5,2 is 10.

→\;\Large{\sf{\frac{5(x-5)}{5(2)}-\frac{2(x-3)}{2(5)} = \frac{1}{5}}}→5(2)5(x−5)−2(5)2(x−3)=51

→\;\Large{\sf{\frac{5x-25}{10}-\frac{2x-6}{10} = \frac{1}{5}}}→105x−25−102x−6=51

→\;\Large{\sf{\frac{5x-25-2x+6}{10} = \frac{1}{5}}}→105x−25−2x+6=51

→\;{\sf{3x-19 = \frac{10}{5}}}→3x−19=510

→\;{\sf{3x = 2+19}}→3x=2+19

→\;{\sf{x = \frac{21}{3}}}→x=321

→\;{\bf{x = 7}}→x=7

Answer 2

Answer:

AnsweR

Given, -1:{\sf{\frac{x-512-\fractx-3}5]= \frac{1}5]} 2x-5-5x-3=51

The LCM of 5,2 is 10. ;Largesf{\frac{5(x-5)] 52)Ffrac(2(x-3)12(5)) = \frac[1{5)} 5(2)5(x-5)-2(5)2(x-3)=51 ;Largesf{frac[5x-25{10}-\frac[2x-6110} = \frac{1{5}}-105x-25-102x-6=51 ;\Largef\sf{\frac{5x-25-2xt6X10} = \frac1 (5)-105x-25-2x+6-=51

Isf{3x-19 \frac{10H5}}-3x-19-510 {\sf[3x = 2+19]}+3x=2+19 :lsf{x = \frac{21{3)]}-x-321 bfx=7)>x=7

I hope it help you........