Question

12345
23451
34512
45123
51234
print the pattern in qbasic​

Answer 1

Explanation:

I did this pattern by constructing an n digit number (the number is 12345 for n=5) and then according to the row number, I simply shifted the digits of this number.

There really is no need to use nested for loops to do this problem. All you need are 2 mutually independent for loops.

Here’s my C++ code…

#include <iostream>

using namespace std;

int main()

{

int n,num=0,k=1;

cout<<"Enter the Number of Rows : ";

cin>>n;

for(int i=1;i<=n;i++)

{

num=num+i;

num=num*10;

k*=10;

}

num=num/10;

k=k/10;

for(int i=1;i<=n;i++)

{

cout<<num<<endl;

num=(num%k)*10+num/k;

}

return 0;

}

Here are a few Test Cases I tried out…