Math, asked by nitinbardia74, 9 months ago

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Answered by HarshMalu

Answer:

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Answered by naunitannu1234

cosA/1+sinA. + 1+sinA/cosA. =2sec A

LHS: cos2A+(1+sin2A)/(1+sinA)cosA. [(a+b2=a2+b2+2ac]

=cos2A+1+2sinA+sin2A/(1+sinA)cosA

=cos2A+sin2A+1+2sinA/(1+sinA)cosA

=1+1+2sinA/(1+sinA)cosA. [cos2A+sin2A=1]

=2+2sinA/(1+sinA)cosA

=2/cosA=2secA =RHS

Hence Proved

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