Question

124 161 224 prime factorazaoin hcf

Answer 1

Answer:

here's the answer

Step-by-step explanation:

First subtract the remainder remainder 5,6 and 7 from the numbers 129, 161, 224 respectively

129 - 5 = 124

161 - 6 = 155

224 - 7 = 217

So the numbers are 124,155 and 217

HCF(124,155,217)

124 = 2 x 2 x 31

155 = 5 x 31

217 = 7 x 31

HCF(124,155,217) = 31

Hence the 31 is the greatest number that will divide 129, 161 & 224 leaving the remainder 5,6 and 7.

hope this helps you ..