Question

124 g of P4 will contain which of the following ..(1)4 atoms of phosphorus (2)4NA atoms of phosphorus (3)NA molecules of phosphorus (4) 1 molecule of phosphorus ....chose the correct option ..and why .?

Answer 1

Answer: The correct answers are Option 2 and 3.

Explanation:

We are given a molecule of phosphorus which is $P_4$

According to the mole concept:

1 mole of a molecule contains $6.022\times 10^{23}$ number of atoms.

In $P_4$ molecule, 4 atoms of phosphorus atoms are present.

So, 1 mole of $P_4$ molecule contains = $4\times 6.022\times 10^{23}=4N_A$ number of phosphorus atoms.

Or, we can say that 1 mole of $P_4$ molecule contains $6.022\times 10^{23}$ or $N_A$ number of molecules.

Hence, the correct answers are Option 2 and 3.

Answer 2

Answer:

Option (2) 4NA atoms of phosphorus

Explanation:

1 molecule of phosphorus weighs = 31 g

4 molecule of phosphorus will weigh = 124 g .... (i)

Also, 1 molecule of phosphorus contains 6.022 × 10^22 atoms or NA atoms ... (ii)

Therefore, from i and ii we get that,

124 g of phosphorus = 4NA atoms of phosphorus

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