1245X70Y is completely divisible by 8 and 9 both then what could be the possible values of X + Y?
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Answer:
Values of X & Y = 4
X + Y = 8
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1245X70Y is completely divisible by 8 and 9 both then what could be the possible values of X + Y
1245X70Y is completely divisible by 9
so sum of digits should be divisible by 9
1 + 2 + 4 + 5 + X + 7 + 0 + Y
= 19 + X + Y
19 + X + Y = 27 or 36
=> X + Y = 8 or X + Y = 17
As number is divisible by 8
so 70Y is also divisible by 8 ( last 3 digits)
704 is divisible by 8
=> Y = 4
=> X + Y = 17 not possible
X + Y = 8
X + 4 = 8
=> X = 4
Values of X & Y = 4
X + Y = 8
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