Math, asked by shubhamkataria2941, 1 year ago

1245X70Y is completely divisible by 8 and 9 both then what could be the possible values of X + Y?

Answers

Answered by amitnrw
0

Answer:

Values of X & Y = 4

X + Y = 8

Step-by-step explanation:

1245X70Y is completely divisible by 8 and 9 both then what could be the possible values of X + Y

1245X70Y is completely divisible by 9

so sum of digits should be divisible by 9

1 + 2 + 4 + 5 + X + 7 + 0 + Y

= 19 + X + Y

19 + X + Y =  27  or 36

=> X + Y = 8   or   X + Y = 17

As number is divisible by 8

so 70Y is also divisible by 8  ( last 3 digits)

704 is divisible by 8

=> Y = 4

=> X + Y = 17 not possible

X + Y = 8

X + 4 = 8

=> X = 4

Values of X & Y = 4

X + Y = 8

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