Question

125 + 2 root 27 aur minus 5 root 5 minus root 3​

Answer 1

Step-by-step explanation:

first we have to make factors and then simplify it

Answer 2

The expression is $\sqrt{125}+2\sqrt{27}-5\sqrt{5}-\sqrt{3}=5\sqrt{3}$.

Step-by-step explanation:

Given : Expression $\sqrt{125}+2\sqrt{27}-5\sqrt{5}-\sqrt{3}$.

To find : Simplify the expression ?

Solution :

Re-write the expression as,

$\sqrt{125}+2\sqrt{27}-5\sqrt{5}-\sqrt{3}=\sqrt{5\times 5\times 5}+2\sqrt{3\times 3\times 3}-5\sqrt{5}-\sqrt{3}$

$\sqrt{125}+2\sqrt{27}-5\sqrt{5}-\sqrt{3}=\sqrt{(5\sqrt{5})^2}+6\sqrt{3}-5\sqrt{5}-\sqrt{3}$

$\sqrt{125}+2\sqrt{27}-5\sqrt{5}-\sqrt{3}=5\sqrt{5}+5\sqrt{3}-5\sqrt{5}$

$\sqrt{125}+2\sqrt{27}-5\sqrt{5}-\sqrt{3}=5\sqrt{3}$

Therefore, the expression is $\sqrt{125}+2\sqrt{27}-5\sqrt{5}-\sqrt{3}=5\sqrt{3}$.

#Learn more

Root 5 + root 3 by root 5 minus root 3 is equal to a + b root 15 find the value of a, b

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