(125/8)×(125/8)^x =(5/2)^18
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Answered by
16
(125/8)¹ × (125/8)^(x) = (5/2)^(18)
(125/8)^(1+x) = (5/2)^(18)
(5/2)^[3(1+x)] = (5/2)^(18)
(5/2)^(3+3x) = (5/2)^(18)
If bases are same, powers are equal.
3 +3x = 18
3x =18-3
3x =15
x =15/3
x =5
I hope this will help you
-by ABHAY
Answered by
6
heya dear
here is your answer
(125/8) × (125/8)^2 = (5/2)^18
(5/2)^3 × (5/2)^ 3×2 = (5/2)^18
(5/2)^3 × (5/2)^6 = (5/2)^18
a^m × a^n = a^(m+n)
so here,
(5/2) ^ 3(1+x) = (5/2)^18
(5/2)^3+3x = (5/2)^18
bases are equal, so we can equate powers
so, 3+3x = 18
3x = 18-3
3x = 15
x = 15/3
x = 5
i hope it helped uh !!
thanks !!
here is your answer
(125/8) × (125/8)^2 = (5/2)^18
(5/2)^3 × (5/2)^ 3×2 = (5/2)^18
(5/2)^3 × (5/2)^6 = (5/2)^18
a^m × a^n = a^(m+n)
so here,
(5/2) ^ 3(1+x) = (5/2)^18
(5/2)^3+3x = (5/2)^18
bases are equal, so we can equate powers
so, 3+3x = 18
3x = 18-3
3x = 15
x = 15/3
x = 5
i hope it helped uh !!
thanks !!
Shreyaparashar:
wrong answer
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