Math, asked by vedprakashyadav551, 6 hours ago

( 125/8) × (125/8)^x = ( 5/2)^18​

Answers

Answered by AarshiNair
1

Answer:

125/8 × (125/8)^x = (5/2)^18

(5/2)³×[(5/2)^3]^x = (5/2)^18

(a^m)^n = a^mn

(5/2)^3 × (5/2)^3x = (5/2)^18

a^m × a^n = a^m+n

=> (5/2)^3+3x = (5/2)^18

=> as bases are equal exponents are equal

=> 3+3x = 18

=> 3x = 15 => x = 15/3 = 5

2)

3^(2x+1) /9=27

3^(2x+1)=27×9

3^(2x+1)=243

(3)^2x+1=(3).^5

3 will cancel out

So,

2x+1=5

2x=5-1

2x=4

x=4/2

x=2

Hope it helps you!

Answered by Itzdarkshadow56
4

Answer:

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