Question

125 cm of a solution contains 0.25 moles of the solute.
What is the concentration of the solution?​

Answer 1

Answer:

Let V mL of a 0.8 M solution contains 100 millimoles of the solute

The number of moles of solute are 1000mL/LVmL×0.8mol/L

But this is equal to 100 millimoles or 0.1 mole.

Hence, 1000mL/LVmL×0.8mol/L=0.1

V=0.80.1×1000=125mL

Thus, 125 mL of a 0.8 M solution contains 100 millimoles of the solute.

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