Question

125 gallons of a mixture contains 20% water. What amount of additional water should be added such that water content is raised to 25%?

Answer 1

Answer:

8.33

Step-by-step explanation:

let x be the amount of water you need to add to what you have to start with, which will be 125 gallons * 0.2 (20%) to get a mixture that is now 25% and the volume will be 125 gallons + x. OK, so the equation that says this is:

(125 gallons * 0.2) + x gallons = (125 gallons + x gallons) * 0.25

25 gallons + x gallons = 31.25 gallons + 0.25x gallons

(x-0.25x) gallons = (31.25–25) gallons

0.75x gallons = 6.25 gallons

x gallons = 8.33 gallon

So you need to add 8.33 gallons of water to the 125 gallons of 20% water to get a solution that is 25% water and the new volume will be 133.33 gallons.

You can do a quick check on this. Originally, you had 125 gallons of 20% water. 125 times 20% is 25 gallons. So, you begin with 25 gallons of water. Then add 8.33 gallons of water. Total water will be 25+8.33 or 33.33 gallons of water. The total volume of the solution will be 125+8.33 or 133.33 gallons. The ratio is 33.33/133.33 or 0.25 which is also 25%.

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