Question

125
per
6. Swati took a loan of Rs 16000 against her insurance policy at the rate of 25/2 percent
annum. Calculate the total compound interest payable by Swati after 3 years.
1​

Answer 1

Answer:

$\red{ \bold{Answer: - }}$

Step-by-step explanation:

$Principle \: (p) \: = \: 16000 \\ \\ Rate \: of \: Interest \: (r) \: = \: \frac{25}{2} \\ \\ Time \: (t) \: = \: 3 \: years \\ \\ Amount = P(1 + \frac{R}{100} ) ^{3} \\ \\ Amount = 16000(1 + \frac{25}{2 \times 100})^{3} \\ \\ = 16000(1 + \frac{25}{200})^{3} \\ \\ = 16000( \frac{225}{200})^{3} \\ \\ = 16000( \frac{9}{8} )^{3} \\ \\ = 16000 \times \frac{9}{8} \times \frac{9}{8} \times \frac{9}{8} \\ \\ 16000 \times \frac{729}{512} \\ \\ \frac{11664000}{512} \\ \\ amount = 22781.25 \\ \\ \\ { \bold{Compound \: Interest \: = \: Amount \: - \: Principle}} \\ \\ \: = 22781.25 - 16000 \\ \\ = 6781.25$

Hope it will help you.....

Answer 2

Answer:

Rs 6,781.28

Step-by-step explanation:

P= Rs 16,000

R= 12.5% p. a

N= 3 years

We Know That

A=P(1 + R/100)n

16,000(1 + 12.5/100)3

16,000(1.125)3

Rs 22,781.25

Now,

CI= A–P

Rs 22,781.25–Rs 16,000

So, your answer is Rs 6,781.25

That is help full for you so please like and rate as