Math, asked by ashwiniPagar, 9 months ago

125
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ALMN - A POR, 9 x A (APOR ) = 16 XA (ALMN), IT OR = 20 then find MN
Areas of two similar triangles are 225 sq.em. 81 sq.em. If a side of the smaller
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Answers

Answered by nakulathul
33

Answer:

hi

hope this helps☺️

Step-by-step explanation:

Answer

Given that ∆LMN and ∆PQR similar triangles.

9 × Area ( ∆PQR) = 16 × Area(∆LMN)

Area of ∆LMN : Area of ∆PQR = 9:16

We know that,

Area of two similar triangles is always Equal to square of their corresponding sides.

Therefore,

Area ( ∆LMN) / Area ( ∆PQR) = (MN/QR)²

9/16 = (MN)² / (20)²

9/16 = (MN)² / 400

(MN)² = 9×400/16

(MN) = ✓9×400/16

MN = 3×20/4

MN = 3 × 5 = 15 cm

HOPE IT WILL HELP YOU....... :-)

Answered by mapeksha112
9

THANK YOU HOPE ITS HELPFUL

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