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ALMN - A POR, 9 x A (APOR ) = 16 XA (ALMN), IT OR = 20 then find MN
Areas of two similar triangles are 225 sq.em. 81 sq.em. If a side of the smaller
5.
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Answer:
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Step-by-step explanation:
Answer
Given that ∆LMN and ∆PQR similar triangles.
9 × Area ( ∆PQR) = 16 × Area(∆LMN)
Area of ∆LMN : Area of ∆PQR = 9:16
We know that,
Area of two similar triangles is always Equal to square of their corresponding sides.
Therefore,
Area ( ∆LMN) / Area ( ∆PQR) = (MN/QR)²
9/16 = (MN)² / (20)²
9/16 = (MN)² / 400
(MN)² = 9×400/16
(MN) = ✓9×400/16
MN = 3×20/4
MN = 3 × 5 = 15 cm
HOPE IT WILL HELP YOU....... :-)
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