125x^3 + 64y^3÷5x+4y
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Answered by
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Solution :-
➜ 125x³ + 64y³ ÷ 5x + 4y
➞ (5x)³ + (4y)³/(5x + 4y)
➞ (5x + 4y) {(5x)² - 5x × 4y + (4y)²}/(5x + 4y)
➞ (5x + 4y) (25x² - 20xy + 16y²)/(5x + 4y)
After cancellation, we get
➞ (25x² - 20xy + 16y²)
∴ The answer of this question is
(25x² - 20xy + 16y²)
Formula used :-
➜ a³ + b³
➞ (a + b) (a² - ab + b²)
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