126:32:11:? Find the anwer
Answers
Answer:
numerical difference between the number on the left and right side gradually becomes greater each time, increasing by 50.
126=76
The difference is 50.
132=32
The difference is 100.
208=58
The difference is now 150.
So if they same pattern persists, the difference will double in numerical quantity again.
261=?
Subtract 200 from positive 261.
The difference is 200.
261=61
The final answer to this puzzle is 61
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There are a number of patterns for this data. One would be that the number in the ones place on the right hand side is the same as the number in the ones place on the left hand side. The number in the tens place can be expressed as the number in the hundreds place plus the number in the ones place if the sum is odd, or that sum divided by two if the sum is even. 1+6=7, 1+2=3, (2+8)/2=5. So, 2+1=3, and therefore the answer is 31. You only gave 3 numbers; there are plenty of patterns to be found.
126=76….132=32…208=58….261=?
The sequence is the deductions of the consecutive multiples of 50 :
126–50= 76,….50*1
132–100=32….50*2
208–150=58…50*3, so the next is...
261–200=61…50*4.
Therefore 61 is the answer.
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If you see the last digit of 126 and 76 ..both are same. Similarly for 132 and 32 also for 208 and 58.
So in our answer last digit should be 1.
Now , if we see carefully 132 = 32 then you can say tht 13 =3 so we can multiply this by 2 and we get 26=6
So we can put 6 in place of 26.
So finally we get 261 = 61.
Thank you. # Keepuzzling
61
Logic is 261 = 26–1+2 = 27 Then 2+7 = 9 and finally its 91
126–50 = 76
132–100 = 32
208–150 = 58
261–200 = 61
Answer:
126:32::11:?
11 : ?
We can find the answer By cross Multiply;-
X
Let the missing Number Be= X
126 × x = 32 × 11.
x =
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