Question

126. The external centre of similitude of the
circle x² + y2 -12x+8y +48 = () and
x² + y2 - 4x +2y -4 = 0 divides the
segment joining centres in the ratio
1) 2:3 2) 3:2 3) -2:3 4)-3:2​

Answer 1

Answer:

126. The external centre of similitude of the circle x² + y2 -12x+8y +48 = () and x² + y2 - 4x +2y ... - did not match any documents.

Suggestions:

Make sure that all words are spelled correctly.

Try different keywords.

Try more general keywords.

Try fewer keywords.

Step-by-step explanation:

please mark me as brainlist

Answer 2

P is the external center of similitude divides C1 and C2 in ratio of r1:r2

externally 2:3

Given:

Similitude of the circle x² + y2 -12x+8y +48 =0  and x² + y2 - 4x +2y -4 = 0 divides the segment joining centers

To Find:

The ratio which divides the circle externally in the ratio r1:r2

Solution:

The center and radius are,

Consider two circles one which is smaller and the other one which is larger,

To get the center and the radius of the circles,

Use common distance formula for radius,

We get,

C1 = (6,-4) , r1 = 2

C2 = (2,-1), r2 = 3

P is the external center of similitude divides C1 and C2 in ratio of r1:r2

externally 2:3

So,

The external formula is,

P = $\frac{ax1 - bx2}{x2-x1} ,\frac{ay2 - by1}{y2 - y1}$

P = ( $\frac{4-18}{2-3} ,\frac{-2+12}{2-3}$)

P = (14, -10)

Hence, the point at which it divides is  (14, -10)

P is the external center of similitude divides C1 and C2 in ratio of r1:r2

externally 2:3

#SPJ2