127 2/ 7 sq cm. of sheet is required to make a hemispherical bowl. Let us write by calculating
the length of diameter of the forepart of the bowl.
Answers
Answer:
Volume of a sphere =3/4×22/7×r³
As hemisphere is 1/4th part of a sphere
So, volume of a hemisphere is 1/4(volume of a spheres)
Step-by-step explanation:
1/4(3/4×22/7×r³)=127²/7
r³=891/7×16/3×7/22=616
r³=6³
r=6
D=2r=12
Given :- 127 2/7 sqcm of sheet is required to make a hemispherical bowl. Let us write by calculating the length of diameter of the forepart of the bowl. ?
Solution :-
we know that,
- curved surface area of a hemispherical bowl is = 2 * π * (radius)² .
- Diameter = 2 * radius .
- Sheet total area = curved surface area of a hemispherical bowl .
Let us assume that, radius of hemisphere is r cm.
so, comparing area , we get,
→ 2 * π * (r)² = 127(2/7)
→ 2 * (22/7) * (r)² = (891/7)
→ 2 * 22 * r² = 891
dividing both sides by 11,
→ 2 * 2 * r² = 81
→ 4r² = 81
→ r² = (81/4)
→ r² = (9/2)²
→ (r)² = (9/2)²
square root both sides,
→ r = (9/2) cm.
therefore,
→ Diameter of hemispherical bowl = 2 * (9/2) = 9 cm. (Ans.)
Hence, the diameter of the forepart of the bowl is 9 cm.
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