(128)^2 - (72)^2
plz answer fast with full method
Answers
Answered by
4
Let a=128
b=72
a^2-b^2=(a+b)(a-b)=(128+72)(128-72)
=(200)(56)
=11200
Hope this help you mate
b=72
a^2-b^2=(a+b)(a-b)=(128+72)(128-72)
=(200)(56)
=11200
Hope this help you mate
Answered by
9
(128)^2 - (72)^2
a^2-b^2 = (a+b) (a-b)
(128+72) ( 128-72)
(200) (56)
11,200.
a^2-b^2 = (a+b) (a-b)
(128+72) ( 128-72)
(200) (56)
11,200.
Anonymous:
Nice answer!
thank you
Nice one! Keep it up. :clap:
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