Question

128 (3a+4b)² - 98(a-b)² factorise ​

Answer 1

Answer:

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

 (128 • ((3a + 4b)2)) -  98 • (a - b)2

STEP

2

:

Equation at the end of step 2

 128 • (3a + 4b)2 -  98 • (a - b)2

STEP

3

:

3.1     Evaluate :  (3a+4b)2   =    9a2+24ab+16b2

3.2     Evaluate :  (a-b)2   =    a2-2ab+b2

STEP

4

:

Pulling out like terms

4.1     Pull out like factors :

  1054a2 + 3268ab + 1950b2  =   2 • (527a2 + 1634ab + 975b2)

Trying to factor a multi variable polynomial :

4.2    Factoring    527a2 + 1634ab + 975b2

Try to factor this multi-variable trinomial using trial and error

Found a factorization  :  (31a + 25b)•(17a + 39b)

Final result :

 2 • (31a + 25b) • (17a + 39b)