Question

128) If x = (123456789) (76543211) + (23456789)², then find
the number of zeroes in
$\sqrt{4}$

x?
(a) 3
(b) 4
(c) 5
(d) 1
(Andhra Pradesh, Telangana)​

Answer 1

Answer:

hope it helps

Step-by-step explanation:

x=(123456789)(76543211)+(23456789)²

=(1000000+23456789). (1000000-23456789)+(23456789)²

=(1000000)²-(23456789)²+(23456789)²

x=(1000000)²=(10⁶)²=10¹²

No. of zeroes in ⁴✓x is 3 zeroes

⁴✓x=⁴✓10¹²=10³