1280 when divided by a smallest number becomes perfect square
Answers
Answered by
0
prime factor of 1280 is
2×2×2×2×2×2×2×2 ×5
here,
![\sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 } \\ \\ 2 \times 2 \times 2 \times 2 \sqrt{5} \\ \\ \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 } \\ \\ 2 \times 2 \times 2 \times 2 \sqrt{5} \\ \\](https://tex.z-dn.net/?f=+%5Csqrt%7B2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+5+%7D+%5C%5C+%5C%5C+2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+2+%5Csqrt%7B5%7D+%5C%5C+%5C%5C+)
5 is left to he paired if we removed 5 by divided it by 5 it will be a perfect square
2×2×2×2×2×2×2×2 ×5
here,
5 is left to he paired if we removed 5 by divided it by 5 it will be a perfect square
Similar questions
English,
8 months ago
English,
8 months ago
Social Sciences,
8 months ago
English,
1 year ago
Social Sciences,
1 year ago