Question

128x² -98(2y -3) ² factorisation ​

Answer 1

Step-by-step explanation:

$128x {}^{2} - 98(2y - 3) {}^{2}$

=2{64x^2—49(2y—3)^2}

=2[{8x}^2—{7(2y—3)}^2]

=2{8x+7(2y—3)} {8x—7(2y—3)}

=2{8x+14y—21} {8x—14y+21}