(1296)× (-¹/²)× (-¹/⁴)ײ
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Using Pythagoras theorem in right triangle ABC, we obtain
AC
2
=AB
2
+BC
2
⇒(5+2)
2
+(2−t)
2
={(5−2)
2
+(2+2)
2
}+{(2+2)
2
+(−2−t)
2
}
⇒49+(4−4t+t
2
)=(9+16)+(16+4+4t+t
2
)
⇒t
2
−4t+53=t
2
+4t×45
⇒−8t=−8
⇒t=1
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