Math, asked by amritvjayraj, 2 months ago

1296 toffees were distributed amongst A, B, C and D such that A got twice as much as C and B got thrice as much as D. If A got 20 less toffees than B, find the sum of toffees with A and D.​

Answers

Answered by amitnrw
1

Given : 1296 toffees were distributed amongst A, B, C and D such that A got twice as much as C and B got thrice as much as D. If A got 20 less toffees than B,

To find :  the sum of toffees with A and D.

Solution:

A got twice as much as C

=> A  = 2C

     B got thrice as much as D

=> B = 3D

A got 20 less toffees than B

A   = B  - 20

=> 2C = 3D  - 20    

Total A + B + C + D  = 1296

=> 2C   + 3D  + C  + D  = 1296

=> 3C  + 4D  = 1296

2C = 3D  - 20      => 6C  = 9D  - 60

3C  + 4D  = 1296   => 6C  +  8D  = 2592

=> 9D  - 60 + 8D  = 2592

=> 17D  = 2652

=> D  = 156

B = 3D = 3 * 156 = 468

A = B - 20  = 468 - 20 = 448

A + D = 448 + 156

=> A + D = 604

A 448

B 468

C 224

D 156

 sum of toffees with A and D is 604

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