12980028 124928 (5) | ENGLISH (10) 139,28263 on the wire? 236. A wire suspended from a support is stretched vertically by 1.6 mm. If the elastic energy stored in the wire is 0.2 J, wha is the force applied (A) 150 N B) 250 N C) 200 N - 300 N
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Answer:
the correct answer is B) 250 N
Explanation:
E= (1/2) x F x ∆l
0.2 J =(1/2) x F x (1.6 *10^(-3)m)
we calculate and get :
F=250N
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