Question

(12a + 17 b) square - ( 12a - 17b) square with standard identities
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Answer 1

$Given \: (12a+17b)^{2} - (12a-17b)^{2}$

$= [ (12a+17b)+(12a-17b)] [ (12a+17b)-(12a-17b)]$

/* By algebraic identity */

$\boxed{\pink{ x^{2} - y^{2} = (x+y)(x-y) }}$

$= (12a+17b+12a-17b)(12a+17b-12a-17b)$

$= 24a \times 17b$

$= 408 ab$

Therefore .,

$\red{ (12a+17b)^{2} - (12a-17b)^{2}}$

$\green {= 408 ab}$

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