Question

12a^2b(a^2 + 15b + 56) ÷ 3ab(a + 7)​

Answer 1

$\frac{12 {a}^{2}b( {a}^{2} + 15b + 56 )}{3ab(a + 7)} \\ \\ \frac{4a( {a}^{2} + 15b + 56) }{a + 7}$

Answer 2

Hope this helps....