Math, asked by rajat20112, 4 months ago

12a^2b(a^2 + 15b + 56) ÷ 3ab(a + 7)

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Answered by Anonymous

2

$\frac{12 {a}^{2}b( {a}^{2} + 15b + 56 )}{3ab(a + 7)} \\ \\ \frac{4a( {a}^{2} + 15b + 56) }{a + 7} \\ \\$

Answered by sriharshamallavarapu

2

Hope this helps....

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