Question

12abc - 6a²b²c²+ 3a³b³c³​

Answer 1

Answer:

It's very simple...

Step-by-step explanation:

$12abc - 6 {a}^{2} {b}^{2} {c}^{2} + 3 {a}^{3} {b}^{3} {c}^{3}$

Factor out 3abc from the expression

Solution :

$3abc(4 - 2abc + {a}^{2} {b}^{2} {c}^{2} )$

Here is your answer...