Question

12abx2-(9a2-8b2)x-6ab=0
find the roots by using quadratic formula.class 10th rs aggrawal ex 4B​

Answer 1

12 abx2 - (9a2 - 8b2)x - 6ab = 0

Comparing with Ax2 + Bx + C = 0, we get

A = 12 ab, B = -(9a2 - 8b2), C = -6 ab

Using the quadratic formula, x=−B±B2−4AC√2A

we get ⇒x=−(−(9a2−8b2)}

±(−(9a2−8b2))2−4(12ab)(−6ab)√2(12ab)

=9a2−8b2±81a4+64b4−144a2b2+288a2b2√24ah

=9a2−8b2±(9a2+8b2)2√24ab

=9a2−8b2±(9a2+8b2)24ab

=9a2−8b2+9a2+8b224ab

=9a2−8b2−9a2−8b224ab

=18a224ab,−16b224ab=3a4b,−2b3a

∴ the solution of the given equation are 3a4b and −2b3a.

Answer 2

Step-by-step explanation:

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