12b➕15-3.b^2 ans -3(b-5)(b➕1)
Answers
Answered by
2
12b+15-3b²=0
3b²-12b-15=0
b²-4b-5=0
b²-5b+b-5=0
b(b-5)+1(b-5)=0
(b-5)(b+1)
I hope this helps you
Thank youu
3b²-12b-15=0
b²-4b-5=0
b²-5b+b-5=0
b(b-5)+1(b-5)=0
(b-5)(b+1)
I hope this helps you
Thank youu
Similar questions