Question

(-12b^6÷b^4)-[(b^4-b^2)÷b^2]​

Answer 1

Answer:

(-12b⁶/b⁴) - [(b⁴ - b²)/b²] = [1 - 13b²]

Step-by-step explanation:

Before solving this Question we should know certain important results,

a^m ÷ a^n = a^(m - n)

Now, we have,

(-12b⁶/b⁴) - [(b⁴ - b²)/b²]

(-12b^(6 - 4)) - [(b²(b² - 1))/b²]

b² cancels out,

(-12b²) - (b² - 1)

(-12b²) - b² + 1

-13b² + 1

1 - 13b²

Hence,

(-12b⁶/b⁴) - [(b⁴ - b²)/b²] = [1 - 13b²]

Hope it helped and believing you understood it........All the best