Question

12g carbon reacts with of oxygen forms 44g of carbondioxide
a) which law of chenical combination is applicable here?
​

Answer 1

Explanation:

Given,

12g C combines with 64g S to give CS

2

12g C combines with 32g O to give CO

2

Also, 10gS combines with 10gO to give SO

2

In CS

2

C:S=12:64=3:16

In CO

2

C:O=12:32=3:8

From, CS

2

& CO

2

, S:O=16:8=2:1

Also in SO

2

S:O=10:10=1:1

⇒2:1 is multiple of 1:1

1

1

×2=

1

2

⇒ Law of reciprocal proportions is illustrated here.