12g of Carbon react with 16g of Oxygen, how much carbon monoxide (CO) is formed? *
Answers
Answer:28g
Explanation: one mole carbon reacts with half mole of O2 gives rise to one mole of carbon monoxide.
Answer:
1 mole CO or 28 g CO is formed
Explanation:
The reaction taking place here is as follows:
C + 1/2 O₂ -----> CO
Thus, for every 1 mole of solid Carbon, we need 1/2 mole of O₂ gas to form one unit mole of CO gas
We have taken 12g of carbon and 16g of dioxygen as per the question
Therefore,
No of moles of carbon taken = mass of C / mol. wt. of C = 12/12 = 1 mol
No of moles of dioxygen taken = mass of O₂ / mol. wt. of O₂ = 16/32 = 1/2 mol
Thus,
1 mole C and 1/2 mole O₂ gas will form 1 mole of CO gas
mass of 1 mole of CO gas is same as molecular mass of CO gas
Therefore, amount of CO gas formed will be 28g
To verify, the law of conservation of mass proves right for the equation.
I hope this answer helps. Happy Chemistry!!