Question

.12g of Mg reacts with dilute H2SO4 to produce H2 gas.The amount of H2 gas produced is?​

Answer 1

Answer:

The reaction of interest is:

Mg + H2SO4 → MgSO4 + H2

The stoichiometry for Mg to H2 is 1:1 so for each mole of Mg, you will obtain 1 mole of H2. So, all you need to know is how many moles of Mg corresponds to 12 grams. The molecular weight of Mg is 24.3 so 12 grams is 0.494 mole. So, since for every mole of Mg will result in one mole of H2, then, 0.494 mol of Mg will result in the formation of 0.494 mol of H2.

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Answer 2

Answer:

The molecular weight of Mg is 24.3 so 12 grams is 0.494 mole. So, since for every mole of Mg will result in one mole of H2, then, 0.494 mol of Mg will result in the formation of 0.494 mol of H2

Explanation:

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